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What will be the output of the following C code?
    #include <stdio.h>
    int main()
    {
        int i = 10;
        int *p = &i;
        printf("%d\n", *p++);
    }
  • a)
    10
  • b)
    11
  • c)
    Garbage value
  • d)
    Address of i
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
What will be the output of the following C code? #include <stdio.h...


Explanation:

Initialization:
- The code initializes an integer variable `i` with the value 10.
- It then declares a pointer `p` to an integer and assigns the address of `i` to `p`.

Print Statement:
- The `printf` statement prints the value pointed to by `p` and then increments the pointer `p` by one.
- The output of the `printf` statement will be the value at the memory location pointed to by `p`, which is the value of `i` (i.e., 10).

Therefore, the output of the code will be:
10
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What will be the output of the following C code? #include <stdio.h> int main() { int i = 10; int *p = &i; printf("%d\n", *p++); }a)10b)11c)Garbage valued)Address of iCorrect answer is option 'A'. Can you explain this answer?
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